हिंदी

The Probability that a Leap Year Will Have 53 Fridays Or 53 Saturdays is (A) 2/7 (B) 3/7 (C) 4/7 (D) 1/7

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प्रश्न

The probability that a leap year will have 53 Fridays or 53 Saturdays is

विकल्प

  •  2/7

  •  3/7

  • 4/7

  • 1/7

     
MCQ
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उत्तर

3/7
We know that a leap year has 366 days (i.e. 7 \[\times\]  52 + 2) = 52 weeks and 2 extra days
The sample space for these 2 extra days is given below:
S = {(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday)}
There are 7 cases.
∴ n(S) = 7
Let E be the event that the leap year has 53 Fridays or 53 Saturdays.
E = { (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday)}
i.e. n(E) = 3

\[\therefore P\left( E \right) = \frac{n\left( E \right)}{n\left( S \right)} = \frac{3}{7}\]

Hence, the probability that a leap year has 53 Fridays or 53 Saturdays is \[\frac{3}{7}\] . 

 

 

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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 33: Probability - Exercise 33.6 [पृष्ठ ७२]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 33 Probability
Exercise 33.6 | Q 18 | पृष्ठ ७२

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