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In a Simultaneous Throw of a Pair of Dice, Find the Probability of Getting:(I) 8 as the Sum

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प्रश्न

In a simultaneous throw of a pair of dice, find the probability of getting:

8 as the sum

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उत्तर

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36


 Let E1 = event of getting 8 as the sum.
Then E1 = {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}
i.e. (E1) = 5

\[\therefore P\left( E_1 \right) = \frac{n\left( E_1 \right)}{n\left( S \right)} = \frac{5}{36}\]

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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 33: Probability - Exercise 33.3 [पृष्ठ ४५]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 33 Probability
Exercise 33.3 | Q 2.01 | पृष्ठ ४५

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