Question

In a simultaneous throw of a pair of dice, find the probability of getting:

8 as the sum

Answer 1

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

 Let E₁ = event of getting 8 as the sum.
Then E₁ = {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}
i.e. n (E₁) = 5

\[\therefore P\left( E_1 \right) = \frac{n\left( E_1 \right)}{n\left( S \right)} = \frac{5}{36}\]