Question

In a simultaneous throw of a pair of dice, find the probability of getting a sum more than 6

Answer 1

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

 Let E₉ = event of getting a sum less than 6
Then E₉ = {(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)}
i.e. n (E₉) = 10

\[\therefore P\left( E_9 \right) = \frac{n\left( E_9 \right)}{n\left( S \right)} = \frac{10}{36} = \frac{5}{18}\]