Question

In a simultaneous throw of a pair of dice, find the probability of getting odd number on the first and 6 on the second

Answer 1

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

 Let E₁₃ = event of getting an odd number on the first throw and 6 on the second
 Then E₁₃ = {(1,6), (3, 6), (5, 6)}
         i.e. n (E₁₃) = 3

\[\therefore P\left( E_{13} \right) = \frac{n\left( E_{13} \right)}{n\left( S \right)} = \frac{3}{36} = \frac{1}{12}\]