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In a Simultaneous Throw of a Pair of Dice, Find the Probability of Getting:(Ix) a Sum More than 6

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Question

In a simultaneous throw of a pair of dice, find the probability of getting a sum more than 6

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Solution

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

 Let E9 = event of getting a sum less than 6
Then E9 = {(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)}
i.e. n (E9) = 10

\[\therefore P\left( E_9 \right) = \frac{n\left( E_9 \right)}{n\left( S \right)} = \frac{10}{36} = \frac{5}{18}\]

 

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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
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Chapter 33: Probability - Exercise 33.3 [Page 45]

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R.D. Sharma Mathematics [English] Class 11
Chapter 33 Probability
Exercise 33.3 | Q 2.09 | Page 45

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