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A Box Contains 6 Red Marbles Numbered 1 Through 6 and 4 White Marbles Numbered from 12 Through 15. Find the Probability that a Marble Drawn is White and Odd Numbered .

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Question

A box contains 6 red marbles numbered 1 through 6 and 4 white marbles numbered from 12 through 15. Find the probability that a marble drawn is white and odd numbered .

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Solution

Total number of marbles = (6 + 4) = 10
Let S be the sample space.
Then n(S) = number of ways of selecting one marble out of 10 = 10C1 = 10 ways

Let E2 = event of getting a white marble, which is odd numbered.
i.e. E2 = {13, 15}
∴  n(E2) = 2
Hence, required probability = \[\frac{n\left( E_2 \right)}{n\left( S \right)} = \frac{2}{10} = \frac{1}{5}\]

 

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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
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Chapter 33: Probability - Exercise 33.3 [Page 47]

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R.D. Sharma Mathematics [English] Class 11
Chapter 33 Probability
Exercise 33.3 | Q 37.2 | Page 47

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