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Question
A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine P(not A).
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Solution
P(A) = 0.42, P(B) = 0.48
P(A and B) = P(A ∩ B) = 0.16
P(not A) = P(A’) = 1 – P(A)
= 1 – 0.42
= 0.58
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