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Question
Two dice are thrown. Find the odds in favour of getting the sum What are the odds against getting the sum 6?
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Solution
Let A be the event of 'getting the sum 6.
Then A= {(1, 5), (5, 1), (2, 4), (4, 2), (3, 3)}
Here, there are five favourable outcomes, while there (36 – 5 =) 31 unfavourable outcomes.
∴ Odds against getting the sum 6 = \[\frac{31}{5} = 31: 5\]
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