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Question
Two dice are thrown simultaneously. The probability of getting a pair of aces is
Options
1/36
1/3
1/6
none of these
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Solution
1/36
When two dice are thrown simultaneously, the sample space associated with the random experiment is given by:
S = {(1, 1), (1, 2), (1, 3) ...(6, 4), (6, 5), (6, 6)}
Clearly, total number of elementary events = 36
Let A be the event of getting a pair of aces.
Then A = {(1, 1)}
∴ n(A) = 1
Hence, required probability = \[\frac{n\left( A \right)}{n\left( S \right)} = \frac{1}{36}\]
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