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Question
In a simultaneous throw of a pair of dice, find the probability of getting:
8 as the sum
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Solution
We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36
Let E1 = event of getting 8 as the sum.
Then E1 = {(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)}
i.e. n (E1) = 5
\[\therefore P\left( E_1 \right) = \frac{n\left( E_1 \right)}{n\left( S \right)} = \frac{5}{36}\]
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