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In a Simultaneous Throw of a Pair of Dice, Find the Probability of Getting:(Xv) a Total of 9 Or 11 - Mathematics

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प्रश्न

In a simultaneous throw of a pair of dice, find the probability of getting a total of 9 or 11

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उत्तर

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

Let E15 = event of getting a total of 9 or 11
Then E15 = {(3, 6), (4, 5), (5, 4) , (5, 6), (6, 3), (6, 5) }
        i.e. (E15) = 6

\[\therefore P\left( E_{15} \right) = \frac{n\left( E_{15} \right)}{n\left( S \right)} = \frac{6}{36} = \frac{1}{6}\]

 

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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
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अध्याय 33: Probability - Exercise 33.3 [पृष्ठ ४५]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 33 Probability
Exercise 33.3 | Q 2.15 | पृष्ठ ४५

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