Question

In a simultaneous throw of a pair of dice, find the probability of getting a number greater than 4 on each die

Answer 1

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

 Let E₁₄ = event of getting a number greater than 4 on each dice
Then E₁₄ = {(5, 5), (5, 6), (6, 5), (6, 6)}
         i.e. n (E₁₄) = 4

\[\therefore P\left( E_{14} \right) = \frac{n\left( E_{14} \right)}{n\left( S \right)} = \frac{4}{36} = \frac{1}{9}\]