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If E and F are events such that P(E) = 14, P(F) = 12 and P(E and F) = 18, find P(E or F) P(not E and not F).

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Question

If E and F are events such that P(E) = `1/4`, P(F) = `1/2` and P(E and F) = `1/8`, find

  1. P(E or F)
  2. P(not E and not F).
Sum
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Solution

P(E) = `1/4`, P(F) =  `1/2`, P(E and F) = P(E ∩ B) = `1/8`

(i) P (E) or F) = P(E U F) = P(E) + P(F) – P(E ∩ F)

= `1/4 + 1/2 - 1/8`

= `(2 + 4 - 1)/8`

= `5/8`

(ii) P(not E and not F) = P(E ∩ F)

= P[(E ∪ F)'] = 1 – P(E ∪ F)

= `1 - 5/8`

= `3/8`

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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
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Chapter 14: Probability - EXERCISE 14.2 [Page 307]

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NCERT Mathematics [English] Class 11
Chapter 14 Probability
EXERCISE 14.2 | Q 15. | Page 307

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