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Question
A and B are two events such that P (A) = 0.54, P (B) = 0.69 and P (A ∩ B) = 0.35. Find
\[P (\bar{ A } \cap \bar{ B } )\]
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Solution
Given:
P (A) = 0.54, P (B) = 0.69 and P (A ∩ B) = 0.35
\[P\left( \bar{A} \cap \bar{ B } \right) = 1 - P\left( A \cup B \right)\]
= 1 - 0.88
= 0.12
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