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Question
An object starting from rest travels 20 m in the first 2 s and 160 m in the next 4 s. What will be the velocity after 7 s from the start?
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Solution
For first 2 s motion of object,
u = 0, f = 2 s, s = 20 m
Using s = `"ut" + 1/2 "at"^2`
we got 20 = `0 + 1/2 "a" xx 2^2`
or a = 10 ms−2
Velocity attained by object at the end of 2s
v = u + at
= 0 + 10 × 2
= 20 ms−1
For next 4s, journey of object,
t' = 4s, u' = 20 ms−1, s' = 160 m
∴ s' = `"u'""t'" + 1/2 "a'""t'"^2`
⇒ 160 = `20 xx 4 + 1/2 xx "a'" xx 4^2`
or 8a' = 80 or a' = 10 ms−2
It implies that acceleration is uniform throughout the journey.
∴ velocity after 7s from start, v = u + at
= 0 + 10 × 7
= 70 ms−1
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