Advertisements
Advertisements
Question
A cheetah starts from, rest, and accelerates at 2 m/s2 for 10 seconds. Calculate :
(a) the final velocity
(b) the distance travelled.
Advertisements
Solution
We have to find the distance travelled by the cheetah. We have the following information given,
So, initial velocity, (u) = 0 m/s
Acceleration, (a) = 2 m/s2
Time taken, (t) = 10 s
(a) So, we can find the final velocity using the relation, v = u + at
Final velocity,
v = 0 + (2) (10)
= 20 m/s
(b) We can calculate the distance travelled by cheetah using the 2nd equation of motion,
`s = ut + 1/2 at^2`
Put the values in above equation to find the distance travelled
`(s) = 0(10) + 1/2(2)(10)^2`
= 100 m
APPEARS IN
RELATED QUESTIONS
When will you say a body is at non-uniform acceleration?
What term is used to denote the change of velocity with time ?
Name the quantity which is measured by the area occupied under the velocity-time graph.
A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.
A bus was moving with a speed of 54 km/h. On applying brakes it stopped in 8 seconds. Calculate the acceleration.
Differentiate between uniform acceleration and variable acceleration.
When is the positive acceleration?
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?

A packet is dropped from a stationary helicopter, hovering at a height ‘h’ from ground level, reaches the ground in 12s. Calculate
- the value of h
- final velocity of packet on reaching the ground. (Take g = 9.8 ms−2)
A stone thrown vertically upwards takes 3 s to attain maximum height. Calculate
- initial velocity of the stone
- maximum height attained by the stone. (Take g = 9.8 ms−2)
