Advertisements
Advertisements
Question
A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s. How far will it travel in this time ?
Advertisements
Solution
We have to find the distance travelled by the train. We have the following information given,
So, initial velocity, (u) = 20 m/s
Acceleration, (a) = 0.5 m/s2
Time taken, (t) = 30 s
We can calculate the distance travelled by using the 2nd equation of motion,
`s = ut + 1/2at^2`
Put the values in above equation to find the distance travelled by the train,
`(s) = 20(30) + 1/2(0.5)(30)^2`
= (600 + 225) m
= 825 m
APPEARS IN
RELATED QUESTIONS
When will you say a body is at non-uniform acceleration?
Fill in the following blank with suitable word :
A motorcycle has a steady……………. of 3 m/s2. This means that every………………. its…………….. increases by………….
What conclusion can you draw about the velocity of a body from the displacement-time graph shown below :
Explain the meaning of the following equation of motion :v = u + at, where symbols have their usual meanings.
Derive the formula s= `ut+1/2at^2` , where the symbols have usual meanings.
When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20 s, then retardation will be :
Can you suggest a real-life example about the motion of a body from the following velocity – time graph?
A stone thrown vertically upwards takes 3 s to attain maximum height. Calculate
- initial velocity of the stone
- maximum height attained by the stone. (Take g = 9.8 ms−2)
Area under a v – t graph represents a physical quantity which has the unit
Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them would be in the ratio of `"u"_1^2 : "u"_2^2` (Assume upward acceleration is –g and downward acceleration to be +g)
