Advertisements
Advertisements
प्रश्न
A cheetah starts from, rest, and accelerates at 2 m/s2 for 10 seconds. Calculate :
(a) the final velocity
(b) the distance travelled.
Advertisements
उत्तर
We have to find the distance travelled by the cheetah. We have the following information given,
So, initial velocity, (u) = 0 m/s
Acceleration, (a) = 2 m/s2
Time taken, (t) = 10 s
(a) So, we can find the final velocity using the relation, v = u + at
Final velocity,
v = 0 + (2) (10)
= 20 m/s
(b) We can calculate the distance travelled by cheetah using the 2nd equation of motion,
`s = ut + 1/2 at^2`
Put the values in above equation to find the distance travelled
`(s) = 0(10) + 1/2(2)(10)^2`
= 100 m
APPEARS IN
संबंधित प्रश्न
A train starting from a railway station and moving with uniform acceleration attains a speed 40 km h−1 in 10 minutes. Find its acceleration.
Fill in the following blank with suitable word :
Velocity is the rate of change of……………………… It is measured in.............. .
Fill in the following blank with suitable word :
If a body moves with uniform velocity, its acceleration is ..............
Explain the meaning of the following equation of motion :v = u + at, where symbols have their usual meanings.
A car acquire a velocity of 72 km per hour in 10 second starting from rest. Find
(1) the acceleration,
(2) the average velocity, and
(3) the distance travelled in this time.
Differentiate between uniform acceleration and variable acceleration.
The figure shows the displacement - time graph for four bodies A, B C and D. In each case state what information do you get about the acceleration (zero, positive or negative).

When is the positive acceleration?
A packet is dropped from a stationary helicopter, hovering at a height ‘h’ from ground level, reaches the ground in 12s. Calculate
- the value of h
- final velocity of packet on reaching the ground. (Take g = 9.8 ms−2)
Area under a v – t graph represents a physical quantity which has the unit
