Advertisements
Advertisements
Question
A spherical marble, of refractive index 1.5 and curvature 1.5 cm, contains a tiny air bubble at its centre. Where will it appear when seen from outside?
Options
1 cm inside
at the centre
`5/3` cm inside
2 cm inside
Advertisements
Solution
`bb(5/3)` cm inside
Explanation:
The refractive index of the marble is 1.5.
One can see the image formed due to the reflection in the spheres.
In order to determine the distance where the image will form, use the lens maker formula.
Hence, `mu_1/v - mu_2/u = (mu_2 - mu_1)/"R"`
Where, refractive index of air = 1, refractive index of glass = 1.5, Radius of the curvature = 1.5 cm
Substituting the values, we get,
`therefore 1/v - 1.5/0.75 = (1 - 1.5)/1.5`
`therefore 1/v - 2 = - 0.5/1.5`
`therefore 1/v - 2 = - 1/3`
`therefore 1/v = - 1/3 + 2`
`therefore 1/v = (- 1 + 6)/3`
`therefore 1/v = 5/3`
Therefore, the tiny bubble will be seen 5/3 cm inside when we see it from the outside.
APPEARS IN
RELATED QUESTIONS
State the conditions required for total internal reflection of light to take place
Name the factors affecting the critical angle for the pair of media.
The figure shows a ray of light falling normally on the face AB of an equilateral glass prism having refractive index`3/2`, placed in water of refractive index `4/3`.Will this ray suffer total internal reflection on striking the face AC? Justify your answer.
State the relation between the critical angle and the absolute refractive index of a medium.
Total internal reflection occurs only when a ray of light passes from a ______ medium to a ______ medium.
(i) Define critical angle.
(ii) State one important factor which affects the critical angle of a given medium.
The diagram below shows a light source P embedded in a rectangular glass block ABCD of critical angle 42°. Complete the path of the ray PQ till it emerges out of the block. [Write necessary angles].
Define critical angle for a given medium.
How does a ray of light bend when it travels from rarer to denser medium
How does a ray of light bend when it travels from when it is normal to the interface of the two media.
Can light be ‘piped’ like sound in a doctor’s stethoscope?
A ray of light incident at an angle of incidence ‘i’ passes through an equilateral glass prism such that the refracted ray inside the prism is parallel to its base and emerges from the prism at an angle of emergence ‘e’.
What can you say about the value of the angle of deviation in such a situation?
Name the factors affecting the critical angle for the pair of media.
What is meant by the statement, ‘the critical angle for diamond is 24°’?
Choose the correct option.
Consider the following phenomena/ applications: P) Mirage, Q) rainbow, R) Optical fibre and S) glittering of a diamond. Total internal reflection is involved in
Answer the following question.
Under what conditions are total internal reflection possible? Explain it with a suitable example.
Solve Numerical example.
A monochromatic ray of light is incident at 37° on an equilateral prism of refractive index 3/2. Determine angle of emergence and angle of deviation. If angle of prism is adjustable, what should its value be for emergent rays to be just possible for the same angle of incidence?
Observe the given figure and write appropriate phenomenon of light in the box.
Critical angle of light passing from glass to air is maximum for ____________.
The resultant `vec"R"` of `vec"P"` and `vec"Q"` is perpendicular to `vec"P"`. Also `|vec"P"|=|vec"R"|`. The angle between `vec"P"` and `vec"Q"` is ______.
[tan 45° = 1]
A particle is projected such that the horizontal range and vertical height are equal. Then the angle of projection is :
What are the examples of total internal reflection in nature?
A green light is incident from the water to the air-water interface at the critical angle (θ). Select the correct statement.
State the condition under which total internal reflection occurs. Give the mathematical expression for total internal reflection.
The angle made by incident ray of light with normal of the reflecting surface is called ______.
- Assertion (A): Propagation of light through an optical fibre is due to total internal reflection taking place at the core-cladding interface.
- Reason (R): Refractive index of the material of the cladding of the optical fibre is greater than that of the core.
The diagram below shows a fish in the tank and its image seen on the surface of the water.
Name the phenomenon responsible for the formation of this image.
When a ray of light is refracted from one medium to another, then the wavelength changes from 6000 Å to 4000 Å. The critical angle for the interface will be ______.
