Advertisements
Advertisements
Question
A plasmid DNA and a linear DNA (both are of the same size) have one site for a restriction endonuclease. When cut and separated on agarose gel electrophoresis, plasmid shows one DNA band while linear DNA shows two fragments. Explain.
Advertisements
Solution
It is because plasmid is a circular DNA molecule. When cut with enzyme, it becomes linear but does not get fragmented. Whereas, a linear DNA molecule gets cut into two fragments. Hence, a single DNA band is observed for plasmid while two DNA bands are observed for linear DNA in agarose gel.
APPEARS IN
RELATED QUESTIONS
Why is the enzyme cellulase needed for isolating genetic material from plant cells and not form the animal cells?
Mention the difference in the mode of action of exonuclease and endonuclease.
How does a restriction nuclease function? Explain
Explain briefly:
Restriction enzymes and DNA
Answer the following question.
Write the use of restriction endonuclease in the formation of recombinant DNA.
A mixture containing DNA fragments a, b, c and d, with molecular weights of a + b = c, a > b and d > c was subject to agarose get electrophoresis. This position of these fragments from cathode to anode to anode sides of the gel would be ______.
Which of the following radioisotope is not suitable for DNA labeling based studies?
There is a restriction endonudease called as EcoRI. What does co part in it stands for?
DNA fragments separate according to size through?
'Restriction' in Restriction enzyme refers to ______.
The role of DNA ligase in the construction of a recombinant DNA molecule is ______.
Would you choose an exonuclease while producing a recombinant DNA molecule?
How does one visualise DNA on an agarose gel?
Carefully observe the given picture. A mixture of DNA with fragments ranging from 200 base pairs to 2500 base pairs was electrophoresed on agarose gel with the following arrangement.
(a) What result will be obtained on staining with ethidium bromide? Explain with reason.
(b) The above setup was modified and a band with 250 base pairs was obtained at X.
What change(s) were made to the previous design to obtain a band at X? Why did the band appear at position X?
What is elution?
State the importance of elution in this process.
State the principle involved in separation of DNA fragments using gel electrophoresis.
Hind II always cuts DNA molecules at a particular point called recognition sequence and it consists of ______.
