Advertisements
Advertisements
प्रश्न
Why does compound (A) given below not form an oxime?
(A)
Advertisements
उत्तर
Glucose pentaacetate (structure A) does not have a free –OH group at C, and therefore, cannot be converted to the open chain form to give a free –CHO group and hence it does not form the oxime.
(Structure A)
APPEARS IN
संबंधित प्रश्न
Write the reaction that indicates the presence of -CHO group in glucose
Draw the simple Fisher projection formulae of D - (+) - glucose and D - (-) - fructose
Maltose is a
(a) Polysaccharide
(b) Disaccharide
(c) Trisaccharide
(d) Monosaccharide
What do you observe when glucose solution is heated with Tollen’s reagent?
What do you observe when glucose is treated with bromine water?
Answer the following question.
What is the basic structural difference between glucose and fructose?
Which of the following statements is incorrect regarding glucose?
Glucose does not react with ____________.
Glucose reacts with acetic anhydride to form ______.
Which of the following properties of glucose cannot be explained by its open chain structure?
(i) Glucose does not form hydrogen sulphite with NaHSO3.
(ii) On oxidation with HNO3 glucose gives saccharic acid.
(iii) Glucose is found to exist in two different crystalline forms which are named as α and β.
Reduction of glucose by HI suggest that ____________.
A solution of D-glucose in water rotates the plane polarised light ____________.
The number of chiral carbon atoms present in cyclic structure α-D(+) glucose:
The two forms of D-glucopyranose obtained from the solution of D-glucose are called ____________.
The number of chiral carbons in ß-D(+) glucose is ____________.
In the following reaction, identify A and B:
\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]
Which of the following pairs represents anomers?
On the basis of which evidences D-glucose was assigned the following structure?
\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\phantom{..}\ce{(CHOH)4}\\
|\phantom{....}\\
\phantom{..}\ce{CH2OH}
\end{array}\]
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
