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प्रश्न
Assertion: D (+) – Glucose is dextrorotatory in nature.
Reason: ‘D’ represents its dextrorotatory nature.
पर्याय
Assertion and reason both are correct statements and reason explains the assertion.
Both assertion and reason are wrong statements.
Assertion is correct statement and reason is wrong statement.
Assertion is wrong statement and reason is correct statement.
Assertion and reason both are correct statements but reason does not explain assertion.
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उत्तर
Assertion is correct statement and reason is wrong. statement.
Explanation:
Glucose is correctly named as D(+)-glucose. ‘D’ before the name of glucose represents the configuration whereas ‘(+)’ represents dextrorotatory nature of the molecule. The letters ‘D’ or ‘L’ before the name of any compound indicate the relative configuration of a particular stereoisomer.
APPEARS IN
संबंधित प्रश्न
Write the reaction that indicates the presence of -CHO group in glucose
Draw the simple Fisher projection formulae of D - (+) - glucose and D - (-) - fructose
Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.
What happens when glucose is treated with hydroxylamine?
Differentiable between the following:
Amylose and Amylopectin
What do you observe when glucose solution is heated with Tollen’s reagent?
Answer the following question.
What is the basic structural difference between glucose and fructose?
Write the reaction involved when D-glucose is treated with the following reagent:
Br2 water
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
A solution of D-glucose in water rotates the plane polarised light ____________.
The two forms of D-glucopyranose obtained from the solution of D-glucose are called ____________.
Which one of the following reactions is not explained by the open chain Structure of glucose?
How will you distinguish 1° and 2° hydroxyl groups present in glucose? Explain with reactions.
On the basis of which evidences D-glucose was assigned the following structure?
\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\phantom{..}\ce{(CHOH)4}\\
|\phantom{....}\\
\phantom{..}\ce{CH2OH}
\end{array}\]
What happens when D-glucose is treated with the following reagent?
HI
Account for the following:
What happens when D – glucose is treated with the following reagents
HNO3
Consider the following reactions:
(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]
(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]
(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]
'X, 'Y' and 'Z' in these reactions are respectively:
Glucose with excess of phenyl hydrazine forms ______.
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
