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प्रश्न
Assertion: D (+) – Glucose is dextrorotatory in nature.
Reason: ‘D’ represents its dextrorotatory nature.
पर्याय
Assertion and reason both are correct statements and reason explains the assertion.
Both assertion and reason are wrong statements.
Assertion is correct statement and reason is wrong statement.
Assertion is wrong statement and reason is correct statement.
Assertion and reason both are correct statements but reason does not explain assertion.
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उत्तर
Assertion is correct statement and reason is wrong. statement.
Explanation:
Glucose is correctly named as D(+)-glucose. ‘D’ before the name of glucose represents the configuration whereas ‘(+)’ represents dextrorotatory nature of the molecule. The letters ‘D’ or ‘L’ before the name of any compound indicate the relative configuration of a particular stereoisomer.
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संबंधित प्रश्न
Draw the simple Fisher projection formulae of D - (+) - glucose and D - (-) - fructose
What happens when glucose is treated with hydroxylamine?
What do you observe when glucose solution is heated with Tollen’s reagent?
The number of asymmetric carbon atom(s) below the figure is/are
Acetylation of glucose yields ____________.
Which one of the following compounds is different from the rest?
Glucose does not react with ____________.
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
The α-D glucose and β-D glucose differ from each other due to difference in carbon atom with respect to its ____________.
The number of chiral carbons in ß-D(+) glucose is ____________.
Why does compound (A) given below not form an oxime?
(A)
How will you distinguish 1° and 2° hydroxyl groups present in glucose? Explain with reactions.
On the basis of which evidences D-glucose was assigned the following structure?
\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\phantom{..}\ce{(CHOH)4}\\
|\phantom{....}\\
\phantom{..}\ce{CH2OH}
\end{array}\]
What happens when D-glucose is treated with the following reagent?
HI
Account for the following:
There are 5 OH groups in glucose
Consider the following reactions:
(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]
(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]
(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]
'X, 'Y' and 'Z' in these reactions are respectively:
When D-glucose reacts with HI, it forms ______.
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
