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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Assertion: D (+) – Glucose is dextrorotatory in nature. Reason: ‘D’ represents its dextrorotatory nature. - Chemistry

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प्रश्न

Assertion: D (+) – Glucose is dextrorotatory in nature.

Reason: ‘D’ represents its dextrorotatory nature.

पर्याय

  • Assertion and reason both are correct statements and reason explains the assertion.

  • Both assertion and reason are wrong statements.

  • Assertion is correct statement and reason is wrong statement.

  • Assertion is wrong statement and reason is correct statement.

  • Assertion and reason both are correct statements but reason does not explain assertion.

MCQ
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उत्तर

Assertion is correct statement and reason is wrong. statement.

Explanation:

Glucose is correctly named as D(+)-glucose. ‘D’ before the name of glucose represents the configuration whereas ‘(+)’ represents dextrorotatory nature of the molecule. The letters ‘D’ or ‘L’ before the name of any compound indicate the relative configuration of a particular stereoisomer.

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पाठ 14: Biomolecules - Multiple Choice Questions (Type - I) [पृष्ठ २१२]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 14 Biomolecules
Multiple Choice Questions (Type - I) | Q 60 | पृष्ठ २१२

संबंधित प्रश्‍न

What do you observe when glucose is treated with bromine water?


Answer the following question.
What is the basic structural difference between glucose and fructose?


Write the reaction involved when D-glucose is treated with the following reagent:

(CH3CO)2O


The following compound can be called as:


The spatial arrangement of the given molecule is denoted by:


The number of asymmetric carbon atom(s) below the figure is/are


What is the most abundant organic compound on earth?


Which of the following statements is incorrect regarding glucose?


The α-D glucose and β-D glucose differ from each other due to difference in carbon atom with respect to its ____________.


Choose the correct relationship for glucose and fructose:


The number of chiral carbons in ß-D(+) glucose is ____________.


Which one is correct?


In the following reaction, identify A and B:

\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]


How will you distinguish 1° and 2° hydroxyl groups present in glucose? Explain with reactions.


What happens when D-glucose is treated with the following reagent?

HI


Account for the following:

What happens when D – glucose is treated with the following reagents

Bromine water


Consider the following reactions:

(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]

(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]

(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]

'X, 'Y' and 'Z' in these reactions are respectively:


Give a reason for the following observations:

Penta-acetate of glucose does not react with hydroxylamine.


The reagents with which glucose does not react to give the corresponding tests/products are:

  1. Tollen’s reagent
  2. Schiff’s reagent
  3. HCN
  4. NH2OH
  5. NaHSO3

Choose the correct options from the given below:


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