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प्रश्न
Differentiable between the following:
Amylose and Amylopectin
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उत्तर १
Amylose:
- Water soluble components
- Constitutes 15-20% of starch
Amylopectin:
- Water insoluble component
- Constitutes 80-85% starch.
उत्तर २
| Amylose | Amylopectin | |
| (a) | Only C1− C4 glycosidic linkage | C1− C4 glycosidic linkage but, branching occurs by C1− C6 glycosidic linkage |
| (b) | Water-soluble component of starch (15-20%) | Water-insoluble component of starch (80-85%) |
संबंधित प्रश्न
Write the reaction that indicates the presence of -CHO group in glucose
What do you observe when glucose is treated with bromine water?
Acetylation of glucose yields ____________.
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
Which is the least stable form of glucose?
A solution of D-glucose in water rotates the plane polarised light ____________.
The two forms of D-glucopyranose obtained from the solution of D-glucose are called ____________.
Assertion: D (+) – Glucose is dextrorotatory in nature.
Reason: ‘D’ represents its dextrorotatory nature.
Account for the following:
What happens when D – glucose is treated with the following reagents
Bromine water
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
