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प्रश्न
Differentiable between the following:
Amylose and Amylopectin
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उत्तर १
Amylose:
- Water soluble components
- Constitutes 15-20% of starch
Amylopectin:
- Water insoluble component
- Constitutes 80-85% starch.
उत्तर २
| Amylose | Amylopectin | |
| (a) | Only C1− C4 glycosidic linkage | C1− C4 glycosidic linkage but, branching occurs by C1− C6 glycosidic linkage |
| (b) | Water-soluble component of starch (15-20%) | Water-insoluble component of starch (80-85%) |
संबंधित प्रश्न
Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.
Write the reactions involved when D-glucose is treated with the following reagent:
H2N-OH
Glucose does not give Schiff’s test because of the formation of cyclic ____________.
Which one of the following compounds is different from the rest?
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
Which of the following reactions of glucose can be explained only by its cyclic structure?
Which is the least stable form of glucose?
The two forms of D-glucopyranose obtained from the solution of D-glucose are called ____________.
Choose the correct relationship for glucose and fructose:
In the following reaction, identify A and B:
\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]
