हिंदी

Draw the simple Fisher projection formulae of D - (+) - glucose and D - (-) - fructose - Chemistry

Advertisements
Advertisements

प्रश्न

Draw the simple Fisher projection formulae of D - (+) - glucose and D - (-) - fructose

Advertisements

उत्तर

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2013-2014 (October)

APPEARS IN

संबंधित प्रश्न

Write the reaction that indicates the presence of -CHO group in glucose


What happens when glucose is treated with hydroxylamine?


Maltose is a 

(a) Polysaccharide

(b) Disaccharide

(c) Trisaccharide

(d) Monosaccharide


Enlist the properties of glucose that can not be explained on the basis of open chain structure of it


What do you observe when glucose is treated with bromine water?


Answer the following question.
What is the basic structural difference between glucose and fructose?


Write the reaction involved when D-glucose is treated with the following reagent:

(CH3CO)2O


The following compound can be called as:


The spatial arrangement of the given molecule is denoted by:


Glucose does not give Schiff’s test because of the formation of cyclic ____________.


Which of the following statements is incorrect regarding glucose?


The symbols D and L represents ____________.


When glucose reacts with bromine water, the main product is ____________.


Reduction of glucose by HI suggest that ____________.


A solution of D-glucose in water rotates the plane polarised light ____________.


Which one is correct?


Which one of the following reactions is not explained by the open chain Structure of glucose?


In the following reaction, identify A and B:

\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]


Three structures are given below in which two glucose units are linked. Which of these linkages between glucose units are between C1 and C4 and which linkages are between C1 and C6?

(I)
(II)
(III)

Why does compound (A) given below not form an oxime?


                   (A)


How will you distinguish 1° and 2° hydroxyl groups present in glucose? Explain with reactions.


Write the reactions of D-glucose which can’t be explained by its open-chain structure. How can cyclic structure of glucose explain these reactions?


On the basis of which evidences D-glucose was assigned the following structure?

\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\phantom{..}\ce{(CHOH)4}\\
|\phantom{....}\\
\phantom{..}\ce{CH2OH}
\end{array}\]


Account for the following:

What happens when D – glucose is treated with the following reagents

Bromine water


Consider the following reactions:

(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]

(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]

(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]

'X, 'Y' and 'Z' in these reactions are respectively:


Match List - I with List - II.

  List I   List II
(A) Glucose + HI (I) Gluconic acid
(B) Glucose + Br2 water (II) Glucose pentacetate
(C) Glucose + acetic anhydride (III) Saccharic acid
(D) Glucose + HNO3 (IV) Hexane

Choose the correct answer from the options given below:


When D-glucose reacts with HI, it forms ______.


Give a reason for the following observations:

Penta-acetate of glucose does not react with hydroxylamine.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×