हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Why does compound (A) given below not form an oxime? (A)

Advertisements
Advertisements

प्रश्न

Why does compound (A) given below not form an oxime?


                   (A)

टिप्पणी लिखिए
Advertisements

उत्तर

Glucose pentaacetate (structure A) does not have a free –OH group at C, and therefore, cannot be converted to the open chain form to give a free –CHO group and hence it does not form the oxime.


     (Structure A)

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Biomolecules - Multiple Choice Questions (Type - I) [पृष्ठ २१०]

APPEARS IN

एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 14 Biomolecules
Multiple Choice Questions (Type - I) | Q 43 | पृष्ठ २१०

संबंधित प्रश्न

Maltose is a 

(a) Polysaccharide

(b) Disaccharide

(c) Trisaccharide

(d) Monosaccharide


Write the product when D-glucose reacts with conc. HNO3.


Fill in the blanks by choosing the appropriate word/words from those given in the brackets:  

(iodoform, acetaldehyde, positive, greater, acidic, acetone, disaccharide, negative, increases, glucose, decreases, chloroform, polysaccharide, lactose, lesser, basic, cationic hydrolysis, anionic hydrolysis)

Sucrose is a _________ and yields upon hydrolysis, a mixture of ________ and fructose.


Answer the following question.
What is the basic structural difference between glucose and fructose?


Acetylation of glucose yields ____________.


Glucose does not give Schiff’s test because of the formation of cyclic ____________.


Which of the following statements is incorrect regarding glucose?


Glucose does not react with ____________.


Which of the following reactions of glucose can be explained only by its cyclic structure?


The α-D glucose and β-D glucose differ from each other due to difference in carbon atom with respect to its ____________.


Choose the correct relationship for glucose and fructose:


The number of chiral carbons in ß-D(+) glucose is ____________.


Which of the following pairs represents anomers?


Assertion: D (+) – Glucose is dextrorotatory in nature.

Reason: ‘D’ represents its dextrorotatory nature.


On the basis of which evidences D-glucose was assigned the following structure?

\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\phantom{..}\ce{(CHOH)4}\\
|\phantom{....}\\
\phantom{..}\ce{CH2OH}
\end{array}\]


Account for the following:

What happens when D – glucose is treated with the following reagents

HNO3


Consider the following reactions:

(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]

(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]

(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]

'X, 'Y' and 'Z' in these reactions are respectively:


Glucose with excess of phenyl hydrazine forms ______.


The number of asymmetric carbon atoms in the glucose molecule in open and cyclic form is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×