Advertisements
Advertisements
प्रश्न
Why does compound (A) given below not form an oxime?
(A)
Advertisements
उत्तर
Glucose pentaacetate (structure A) does not have a free –OH group at C, and therefore, cannot be converted to the open chain form to give a free –CHO group and hence it does not form the oxime.
(Structure A)
APPEARS IN
संबंधित प्रश्न
How many moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose?
(a) 2
(b) 5
(c) 10
(d) 2.5
What happens when glucose is treated with hydroxylamine?
Enlist the properties of glucose that can not be explained on the basis of open chain structure of it
Write the product when D-glucose reacts with conc. HNO3.
What do you observe when glucose solution is heated with Tollen’s reagent?
Fill in the blanks by choosing the appropriate word/words from those given in the brackets:
(iodoform, acetaldehyde, positive, greater, acidic, acetone, disaccharide, negative, increases, glucose, decreases, chloroform, polysaccharide, lactose, lesser, basic, cationic hydrolysis, anionic hydrolysis)
Sucrose is a _________ and yields upon hydrolysis, a mixture of ________ and fructose.
Write the reactions involved when D-glucose is treated with the following reagent:
H2N-OH
Choose the appropriate answer(s) for the below representation from the options given
Oxime is formed by treating glucose with ____________.
Glucose does not give Schiff’s test because of the formation of cyclic ____________.
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
Which is the least stable form of glucose?
The number of chiral carbon atoms present in cyclic structure α-D(+) glucose:
The two forms of D-glucopyranose obtained from the solution of D-glucose are called ____________.
Which one is correct?
Which one of the following reactions is not explained by the open chain Structure of glucose?
In the following reaction, identify A and B:
\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]
Account for the following:
What happens when D – glucose is treated with the following reagents
HNO3
The number of asymmetric carbon atoms in the glucose molecule in open and cyclic form is ______.
