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Why does compound (A) given below not form an oxime? (A) - Chemistry

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प्रश्न

Why does compound (A) given below not form an oxime?


                   (A)

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उत्तर

Glucose pentaacetate (structure A) does not have a free –OH group at C, and therefore, cannot be converted to the open chain form to give a free –CHO group and hence it does not form the oxime.


     (Structure A)

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अध्याय 14: Biomolecules - Multiple Choice Questions (Type - I) [पृष्ठ २१०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 14 Biomolecules
Multiple Choice Questions (Type - I) | Q 43 | पृष्ठ २१०

संबंधित प्रश्न

How many moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose?

(a) 2

(b) 5

(c) 10

(d) 2.5


What happens when glucose is treated with hydroxylamine?


The spatial arrangement of the given molecule is denoted by:


Which one of the following compounds is different from the rest?


When glucose reacts with bromine water, the main product is ____________.


Glucose does not react with ____________.


The number of chiral carbon atoms present in cyclic structure α-D(+) glucose:


Choose the correct relationship for glucose and fructose:


Which one of the following reactions is not explained by the open chain Structure of glucose?


Which of the following pairs represents anomers?


On the basis of which evidences D-glucose was assigned the following structure?

\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\phantom{..}\ce{(CHOH)4}\\
|\phantom{....}\\
\phantom{..}\ce{CH2OH}
\end{array}\]


Account for the following:

What happens when D – glucose is treated with the following reagents

Bromine water


Consider the following reactions:

(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]

(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]

(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]

'X, 'Y' and 'Z' in these reactions are respectively:


Glucose with excess of phenyl hydrazine forms ______.


Match List - I with List - II.

  List I   List II
(A) Glucose + HI (I) Gluconic acid
(B) Glucose + Br2 water (II) Glucose pentacetate
(C) Glucose + acetic anhydride (III) Saccharic acid
(D) Glucose + HNO3 (IV) Hexane

Choose the correct answer from the options given below:


Give the reaction of glucose with hydrogen cyanide. Presence of which group is confirmed by this reaction?


Give a reason for the following observations:

Penta-acetate of glucose does not react with hydroxylamine.


The reagents with which glucose does not react to give the corresponding tests/products are:

  1. Tollen’s reagent
  2. Schiff’s reagent
  3. HCN
  4. NH2OH
  5. NaHSO3

Choose the correct options from the given below:


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