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प्रश्न
Why does compound (A) given below not form an oxime?
(A)
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उत्तर
Glucose pentaacetate (structure A) does not have a free –OH group at C, and therefore, cannot be converted to the open chain form to give a free –CHO group and hence it does not form the oxime.
(Structure A)
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संबंधित प्रश्न
Draw the simple Fisher projection formulae of D - (+) - glucose and D - (-) - fructose
Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.
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Write the reaction involved when D-glucose is treated with the following reagent:
Br2 water
Write the reaction involved when D-glucose is treated with the following reagent:
(CH3CO)2O
Choose the appropriate answer(s) for the below representation from the options given
Which of the following statements is incorrect regarding glucose?
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\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]
How will you distinguish 1° and 2° hydroxyl groups present in glucose? Explain with reactions.
What happens when D-glucose is treated with the following reagent?
HI
Account for the following:
There are 5 OH groups in glucose
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Give the reaction of glucose with hydrogen cyanide. Presence of which group is confirmed by this reaction?
