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प्रश्न
Why does compound (A) given below not form an oxime?
(A)
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उत्तर
Glucose pentaacetate (structure A) does not have a free –OH group at C, and therefore, cannot be converted to the open chain form to give a free –CHO group and hence it does not form the oxime.
(Structure A)
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संबंधित प्रश्न
Draw the simple Fisher projection formulae of D - (+) - glucose and D - (-) - fructose
How many moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose?
(a) 2
(b) 5
(c) 10
(d) 2.5
What happens when glucose is treated with hydroxylamine?
Write the reaction involved when D-glucose is treated with the following reagent:
(CH3CO)2O
The spatial arrangement of the given molecule is denoted by:
The number of asymmetric carbon atom(s) below the figure is/are
Which of the following statements is incorrect regarding glucose?
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
The reaction of glucose with red P + HI is called ____________.
A solution of D-glucose in water rotates the plane polarised light ____________.
The number of chiral carbons in ß-D(+) glucose is ____________.
Which one is correct?
Assertion: D (+) – Glucose is dextrorotatory in nature.
Reason: ‘D’ represents its dextrorotatory nature.
Account for the following:
There are 5 OH groups in glucose
The number of asymmetric carbon atoms in the glucose molecule in open and cyclic form is ______.
When D-glucose reacts with HI, it forms ______.
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
