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प्रश्न
Which of the following reactions of glucose can be explained only by its cyclic structure?
विकल्प
Glucose forms pentaacetate
Glucose reacts with hydroxylamine to form an oxime
Pentaacetate of glucose does not react with hydroxylamine
Glucose is oxidised by nitric acid to gluconic acid
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उत्तर
Pentaacetate of glucose does not react with hydroxylamine
Explanation:
The pentaacetate of glucose does not react with hydroxylamine indicating the absence of free –CHO group. This property of glucose can be explained only by its cyclic structure.
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संबंधित प्रश्न
How many moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose?
(a) 2
(b) 5
(c) 10
(d) 2.5
Enlist the properties of glucose that can not be explained on the basis of open chain structure of it
Write the product when D-glucose reacts with conc. HNO3.
Glucose on reaction with HI gives n-hexane. What does it suggest about the structure of glucose?
Fill in the blanks by choosing the appropriate word/words from those given in the brackets:
(iodoform, acetaldehyde, positive, greater, acidic, acetone, disaccharide, negative, increases, glucose, decreases, chloroform, polysaccharide, lactose, lesser, basic, cationic hydrolysis, anionic hydrolysis)
Sucrose is a _________ and yields upon hydrolysis, a mixture of ________ and fructose.
What do you observe when glucose is treated with bromine water?
Oxime is formed by treating glucose with ____________.
Glucose does not give Schiff’s test because of the formation of cyclic ____________.
Which one of the following compounds is different from the rest?
When glucose reacts with bromine water, the main product is ____________.
Glucose does not react with ____________.
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
The reaction of glucose with red P + HI is called ____________.
The two forms of D-glucopyranose obtained from the solution of D-glucose are called ____________.
Which one of the following reactions is not explained by the open chain Structure of glucose?
Write the reactions of D-glucose which can’t be explained by its open-chain structure. How can cyclic structure of glucose explain these reactions?
Consider the following reactions:
(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]
(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]
(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]
'X, 'Y' and 'Z' in these reactions are respectively:
Glucose with excess of phenyl hydrazine forms ______.
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
