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प्रश्न
Which of the following reactions of glucose can be explained only by its cyclic structure?
पर्याय
Glucose forms pentaacetate
Glucose reacts with hydroxylamine to form an oxime
Pentaacetate of glucose does not react with hydroxylamine
Glucose is oxidised by nitric acid to gluconic acid
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उत्तर
Pentaacetate of glucose does not react with hydroxylamine
Explanation:
The pentaacetate of glucose does not react with hydroxylamine indicating the absence of free –CHO group. This property of glucose can be explained only by its cyclic structure.
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संबंधित प्रश्न
Write the reaction that indicates the presence of -CHO group in glucose
Maltose is a
(a) Polysaccharide
(b) Disaccharide
(c) Trisaccharide
(d) Monosaccharide
Enlist the properties of glucose that can not be explained on the basis of open chain structure of it
Differentiable between the following:
Amylose and Amylopectin
Fill in the blanks by choosing the appropriate word/words from those given in the brackets:
(iodoform, acetaldehyde, positive, greater, acidic, acetone, disaccharide, negative, increases, glucose, decreases, chloroform, polysaccharide, lactose, lesser, basic, cationic hydrolysis, anionic hydrolysis)
Sucrose is a _________ and yields upon hydrolysis, a mixture of ________ and fructose.
Write the reaction involved when D-glucose is treated with the following reagent:
(CH3CO)2O
The spatial arrangement of the given molecule is denoted by:
Which of the following statements is incorrect regarding glucose?
The reaction of glucose with red P + HI is called ____________.
Choose the correct relationship for glucose and fructose:
Which one is correct?
In the following reaction, identify A and B:
\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]
Why does compound (A) given below not form an oxime?
(A)
Account for the following:
There are 5 OH groups in glucose
Account for the following:
What happens when D – glucose is treated with the following reagents
Bromine water
Account for the following:
What happens when D – glucose is treated with the following reagents
HNO3
The number of asymmetric carbon atoms in the glucose molecule in open and cyclic form is ______.
Match List - I with List - II.
| List I | List II | ||
| (A) | Glucose + HI | (I) | Gluconic acid |
| (B) | Glucose + Br2 water | (II) | Glucose pentacetate |
| (C) | Glucose + acetic anhydride | (III) | Saccharic acid |
| (D) | Glucose + HNO3 | (IV) | Hexane |
Choose the correct answer from the options given below:
When D-glucose reacts with HI, it forms ______.
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
