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प्रश्न
Maltose is a
(a) Polysaccharide
(b) Disaccharide
(c) Trisaccharide
(d) Monosaccharide
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उत्तर
Disaccharide
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संबंधित प्रश्न
Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.
What happens when glucose is treated with hydroxylamine?
Write the product when D-glucose reacts with conc. HNO3.
The following compound can be called as:
Choose the appropriate answer(s) for the below representation from the options given
What is the most abundant organic compound on earth?
Oxime is formed by treating glucose with ____________.
Acetylation of glucose yields ____________.
Glucose does not give Schiff’s test because of the formation of cyclic ____________.
Which of the following statements is incorrect regarding glucose?
Which one of the following compounds is different from the rest?
Which of the following properties of glucose cannot be explained by its open chain structure?
(i) Glucose does not form hydrogen sulphite with NaHSO3.
(ii) On oxidation with HNO3 glucose gives saccharic acid.
(iii) Glucose is found to exist in two different crystalline forms which are named as α and β.
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
The number of chiral carbon atoms present in cyclic structure α-D(+) glucose:
The α-D glucose and β-D glucose differ from each other due to difference in carbon atom with respect to its ____________.
The two forms of D-glucopyranose obtained from the solution of D-glucose are called ____________.
Choose the correct relationship for glucose and fructose:
The number of chiral carbons in ß-D(+) glucose is ____________.
Which one of the following reactions is not explained by the open chain Structure of glucose?
Which of the following pairs represents anomers?
Assertion: D (+) – Glucose is dextrorotatory in nature.
Reason: ‘D’ represents its dextrorotatory nature.
On the basis of which evidences D-glucose was assigned the following structure?
\[\begin{array}{cc}
\ce{CHO}\\
|\phantom{....}\\
\phantom{..}\ce{(CHOH)4}\\
|\phantom{....}\\
\phantom{..}\ce{CH2OH}
\end{array}\]
Account for the following:
There are 5 OH groups in glucose
Consider the following reactions:
(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]
(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]
(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]
'X, 'Y' and 'Z' in these reactions are respectively:
The number of asymmetric carbon atoms in the glucose molecule in open and cyclic form is ______.
When D-glucose reacts with HI, it forms ______.
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
