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प्रश्न
When D-glucose reacts with HI, it forms ______.
पर्याय
Gluconic acid
n-hexane
Saccharic acid
Iodohexane
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उत्तर
When D-glucose reacts with HI, it forms n-hexane.
Explanation:
On prolonged heating with HI, it forms n-hexane, suggesting that all the six carbon atoms are linked in a straight chain.
\[\begin{array}{cc}
\ce{CHO}\phantom{.................................................}\\
|\phantom{.....................................................}\\
\ce{(CHOH)4 ->[HI,\Delta] \underset{{(n-Hexane)}}{CH3 - CH2 - CH2 - CH2 - CH2 - CH3}}\\
|\phantom{.....................................................}\\
\ce{CH2OH}\phantom{...............................................}
\end{array}\]
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संबंधित प्रश्न
Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.
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(a) Polysaccharide
(b) Disaccharide
(c) Trisaccharide
(d) Monosaccharide
Write the reaction involved when D-glucose is treated with the following reagent:
Br2 water
Write the reactions involved when D-glucose is treated with the following reagent:
H2N-OH
The reaction of glucose with red P + HI is called ____________.
Which of the following reactions of glucose can be explained only by its cyclic structure?
A solution of D-glucose in water rotates the plane polarised light ____________.
Write the reactions of D-glucose which can’t be explained by its open-chain structure. How can cyclic structure of glucose explain these reactions?
The number of asymmetric carbon atoms in the glucose molecule in open and cyclic form is ______.
