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प्रश्न
When D-glucose reacts with HI, it forms ______.
पर्याय
Gluconic acid
n-hexane
Saccharic acid
Iodohexane
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उत्तर
When D-glucose reacts with HI, it forms n-hexane.
Explanation:
On prolonged heating with HI, it forms n-hexane, suggesting that all the six carbon atoms are linked in a straight chain.
\[\begin{array}{cc}
\ce{CHO}\phantom{.................................................}\\
|\phantom{.....................................................}\\
\ce{(CHOH)4 ->[HI,\Delta] \underset{{(n-Hexane)}}{CH3 - CH2 - CH2 - CH2 - CH2 - CH3}}\\
|\phantom{.....................................................}\\
\ce{CH2OH}\phantom{...............................................}
\end{array}\]
APPEARS IN
संबंधित प्रश्न
Draw the simple Fisher projection formulae of D - (+) - glucose and D - (-) - fructose
Enlist the properties of glucose that can not be explained on the basis of open chain structure of it
Answer the following question.
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The number of asymmetric carbon atom(s) below the figure is/are
Oxime is formed by treating glucose with ____________.
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Which one of the following compounds is different from the rest?
The number of chiral carbon atoms present in cyclic structure α-D(+) glucose:
The two forms of D-glucopyranose obtained from the solution of D-glucose are called ____________.
In the following reaction, identify A and B:
\[\begin{array}{cc}
\ce{C6H12O6 ->[Acetic anhydride] A}\\
\downarrow \text{Conc. nitric acid}\phantom{...}\\
\ce{B}\phantom{.................}\end{array}\]
