Advertisements
Advertisements
Question
Which of the following reactions of glucose can be explained only by its cyclic structure?
Options
Glucose forms pentaacetate
Glucose reacts with hydroxylamine to form an oxime
Pentaacetate of glucose does not react with hydroxylamine
Glucose is oxidised by nitric acid to gluconic acid
Advertisements
Solution
Pentaacetate of glucose does not react with hydroxylamine
Explanation:
The pentaacetate of glucose does not react with hydroxylamine indicating the absence of free –CHO group. This property of glucose can be explained only by its cyclic structure.
APPEARS IN
RELATED QUESTIONS
Enumerate the reactions of D-glucose which cannot be explained by its open chain structure.
Answer the following question.
What is the basic structural difference between glucose and fructose?
The symbols D and L represents ____________.
Glucose does not react with ____________.
Glucose is found to exist in two different α and β crystalline forms. These forms can be obtained by:
(i) The α form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(ii) The β form of glucose is obtained by crystallisation from a concentrated solution of glucose at 303 K.
(iii) The β form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
(iv) The α form is obtained by crystallisation from hot and saturated aqueous solution at 371 K.
Reduction of glucose by HI suggest that ____________.
A solution of D-glucose in water rotates the plane polarised light ____________.
Choose the correct relationship for glucose and fructose:
The letter D and L in carbohydrates represent ____________.
Which one is correct?
Which one of the following reactions is not explained by the open chain Structure of glucose?
What happens when D-glucose is treated with the following reagent?
HI
Account for the following:
What happens when D – glucose is treated with the following reagents
Bromine water
Consider the following reactions:
(i) \[\ce{Glucose + R-OH ->[Conc. HNO3] [A] ->[X eq of][(CH3CO)2O] Acetyl derivative}\]
(ii) \[\ce{Glucose ->[Ni/H2] [A] ->[Y eq of][(CH3CO)2O] Acetyl derivative}\]
(iii) \[\ce{Glucose ->[Z eq of][(CH3CO)2O] Acetyl derivative}\]
'X, 'Y' and 'Z' in these reactions are respectively:
Glucose with excess of phenyl hydrazine forms ______.
Match List - I with List - II.
| List I | List II | ||
| (A) | Glucose + HI | (I) | Gluconic acid |
| (B) | Glucose + Br2 water | (II) | Glucose pentacetate |
| (C) | Glucose + acetic anhydride | (III) | Saccharic acid |
| (D) | Glucose + HNO3 | (IV) | Hexane |
Choose the correct answer from the options given below:
When D-glucose reacts with HI, it forms ______.
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
