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Solve the following differential equation: dydxyxdydx=(1+y)2(1+x)2

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प्रश्न

Solve the following differential equation:

`"dy"/"dx" = (1 + "y")^2/(1 + "x")^2`

बेरीज
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उत्तर

`"dy"/"dx" = (1 + "y")^2/(1 + "x")^2`

∴ `1/(1 + "y"^2) "dy" = 1/(1 + "x"^2) "dx"`

Integrating both sides, we get

`int 1/(1 + "y"^2) "dx" = int1/(1 + "x"^2) "dx"`

∴ tan-1 y = tan-1 x + c

This is the general solution.

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पाठ 6: Differential Equations - Exercise 6.3 [पृष्ठ २०१]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Exercise 6.3 | Q 2.01 | पृष्ठ २०१

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