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Find the differential equation of the curve represented by xy = aex + be–x + x2 - Mathematics

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प्रश्न

Find the differential equation of the curve represented by xy = aex + be–x + x2

बेरीज
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उत्तर

Given xy = aex + bex + x2  ........(1)

Where a and b are aribitrary constant,

Differentiate equation (1) twice successively,

Because we have two arbitray constant.

`x ("d"y)/("d"x) + y(1)` = aex – be–x + 2x  .......(2)

`x ("d"^2y)/("d"x^2) + ("d")/("d"x) (1) + ("d"y)/("d"x)` = aex + be–x + 2 

`x ("d"^2y)/("d"x^2) + (2"d"y)/("d"x)` = aex + be–x + 2  ......(3)

From (1), we get xy – x2 = aex + bex  ........(4)

Substituting equation (4) in (3), we get

∴ `x ("d"^2y)/("d"x^2) + (2"d"y)/("d"x) - xy + x^2 - 2` = 0 is the required differential equation.

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पाठ 10: Ordinary Differential Equations - Exercise 10.3 [पृष्ठ १५४]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 10 Ordinary Differential Equations
Exercise 10.3 | Q 8 | पृष्ठ १५४

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