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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

In the following example verify that the given function is a solution of the differential equation. ycosxxxdydxxdydxyy=3cos(logx)+4sin(logx);x2d2ydx2+xdydx+y=0 - Mathematics and Statistics

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प्रश्न

In the following example verify that the given function is a solution of the differential equation.

`"y" = 3 "cos" (log "x") + 4 sin (log "x"); "x"^2 ("d"^2"y")/"dx"^2 + "x" "dy"/"dx" + "y" = 0`

बेरीज
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उत्तर

`"y" = 3 "cos" (log "x") + 4 sin (log "x")`    ...(1)

Differentiating both sides w.r.t. x, we get

`"dy"/"dx" = 3 "d"/"dx" [cos (log "x")] + 4 "d"/"dx" [sin (log "x")]`

`= 3 [- sin (log "x")] "d"/"dx" (log "x") + 4 cos (log "x") "d"/"dx" (log "x")`

`= - 3 sin (log "x") xx 1/"x" + 4 cos (log "x") xx 1/"x"`

∴ `"x" "dy"/"dx" = - 3 sin (log "x") + 4 cos (log "x")`

Differentiating again w.r.t. x, we get,

`"x" "d"/"dx" ("dy"/"dx") + "dy"/"dx" * "d"/"dx" ("x") = - 3 "d"/"dx" [sin (log "x")] + 4 "d"/"dx"[cos (log "x")]`

∴ `"x" ("d"^2"y")/"dx"^2 + "dy"/"dx" xx 1 = - 3 cos (log "x") * "d"/"dx" (log "x") + 4 [- sin (log "x")]* "d"/"dx" (log "x")`

∴ `"x" ("d"^2"y")/"dx"^2 + "dy"/"dx" = - 3 cos (log "x") xx 1/"x" - 4 sin (log "x") xx 1/"x"`

∴ `"x"^2 ("d"^2"y")/"dx"^2 + "x" "dy"/"dx" = - [3 cos (log "x") + 4 sin (log "x")] = - "y"`     ...[By (1)]

∴ `"x"^2 ("d"^2"y")/"dx"^2 + "x" "dy"/"dx" + "y" = 0`

Hence, y = 3 cos (log x) + 4 sin (log x) is a solution of the D.E. `"x"^2 ("d"^2"y")/"dx"^2 + "x" "dy"/"dx" + "y" = 0`

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पाठ 6: Differential Equations - Miscellaneous exercise 2 [पृष्ठ २१७]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Miscellaneous exercise 2 | Q 2.3 | पृष्ठ २१७

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