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Solve the following differential equation: secxtan ydxsecytan xdysec2x⋅tan y dx+sec2y⋅tan x dy=0

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प्रश्न

Solve the following differential equation:

`"sec"^2 "x" * "tan y"  "dx" + "sec"^2 "y" * "tan x"  "dy" = 0` 

बेरीज
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उत्तर

`"sec"^2 "x" * "tan y"  "dx" + "sec"^2 "y" * "tan x"  "dy" = 0`

∴ `("sec"^2 "x")/"tan x" "dx" + ("sec"^2 "y")/"tan y" "dy" = 0` 

Integrating both sides, we get

`int ("sec"^2"x")/"tan x" "dx" + int ("sec"^2 "y")/"tan y" "dy" = "c"_1`

Each of these integrals is of the type

`int ("f"'("x"))/("f"("x))` `"dx"  = log |"f"("x")| + "c"`

∴ the general solution is

log |tan x| + log |tan y| = log c, where c1 = log c,

∴ `log |tan "x" * tan "y"| = log c`

∴ `tan "x" * tan"y" = "c"`

This is the general solution.

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पाठ 6: Differential Equations - Exercise 6.3 [पृष्ठ २०१]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Exercise 6.3 | Q 2.04 | पृष्ठ २०१

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