Advertisements
Advertisements
प्रश्न
Give the IUPAC name of the following ether:

Advertisements
उत्तर
1-Ethoxy-4,4-dimethylcyclohexane
APPEARS IN
संबंधित प्रश्न
Write the IUPAC name of the following compound:

Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - O - CH2 - CH - CH3}\\
\phantom{................}|\\
\phantom{....................}\ce{CH3}
\end{array}\]
Give the IUPAC name of the following ether:
\[\begin{array}{cc}
\ce{C2H5OCH2 - CH - CH3}\\
\phantom{.........}|\\
\phantom{.............}\ce{CH3}
\end{array}\]
Give the IUPAC name of the following ether:

Write the structures of the products when Butan-2-ol reacts with CrO3
Write the IUPAC name of the following :

Propanoic acid to ethylamine.
n-Propyl alcohol and isopropyl alcohol can be chemically distinguished by which reagent?
1-Propanol and 2-propanol can be best distinguished by:
The major product formed by the reaction:
\[\begin{array}{cc}
\ce{CH3CH-CH2Br ->[CH3O^-][CH3OH] is}\\
|\phantom{................}\\
\ce{CH3}\phantom{.............}
\end{array}\]
IUPAC name of the compound is:
\[\begin{array}{cc}
\ce{CH3-CH-OCH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
The correct acidic strength order of the following is:

(I)

(II)

(III)
What happens when benzene diazonium chloride is heated with water?
Arrange the following compounds in decreasing order of acidity.
\[\ce{H2O, ROH, HC ≡ CH}\]
Write steps to carry out the conversion of phenol to aspirin.
Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.
Reason: Bromine polarises in carbon disulphide.
Assertion: Phenols give o- and p-nitrophenol on nitration with conc. \[\ce{HNO3}\] and \[\ce{H2SO4}\] mixture.
Reason: –OH group in phenol is o–, p– directing.
Identify A and B in the following:

Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\phantom{..............}\ce{CH3}\\
\phantom{............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{.....}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{.}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
