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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Name the following compound according to the IUPAC system. OH Br

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प्रश्न

Name the following compound according to the IUPAC system.

एक शब्द/वाक्यांश उत्तर
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उत्तर

3-Bromocyclohexanol

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पाठ 7: Alcohols, Phenols and Ethers - Intext Questions [पृष्ठ १९८]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 7 Alcohols, Phenols and Ethers
Intext Questions | Q 7.3 (iii) | पृष्ठ १९८

संबंधित प्रश्‍न

Write the IUPAC name of the given compound:


Name the following compound according to the IUPAC system.

\[\begin{array}{cc}
\ce{CH3 - C = C - CH2OH}\\
|\phantom{......}|\phantom{.....}\\
\ce{CH3}\phantom{.}\ce{Br}\phantom{....}\\
\end{array}\]


Write the IUPAC name of the following compound:

\[\begin{array}{cc}
\ce{HO - CH2 - CH - CH2 - OH}\\
|\phantom{...}\\
\ce{OH}\phantom{.}\\
\end{array}\]


Write the IUPAC name of the following compound:


Give the IUPAC name of the following ether:

CH3CH2CH2OCH3


Give the IUPAC name of the following ether:


Write structural formulae for Cyclohex-2-en-1-ol.


In a carbinol system of nomenclature tert.butyl alcohol is named as _______________


When ethyl alcohol reacts with acetic acid, the products formed are:


The IUPAC name of the ether CH2 = CH–CH2OCH3 is:


Write steps to carry out the conversion of phenol to aspirin.


Explain why p-nitrophenol is more acidic than phenol.


Assertion: Addition reaction of water to but-1-ene in acidic medium yields butan-1-ol.

Reason: Addition of water in acidic medium proceeds through the formation of primary carbocation.


Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.

Reason: Bromine polarises in carbon disulphide.


How can phenol be converted to aspirin?


Convert the following:

Ethyl alcohol into ethyl acetate.


Draw structure of the following compound.

2. 5-Diethylphenol


Write structural formulae for:

Salicylic acid


Write the IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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