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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Name the following compound according to the IUPAC system. H⁡2⁢C = CH − CH − CH2 − CH2 − CH3 | OH

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प्रश्न

Name the following compound according to the IUPAC system.

\[\begin{array}{cc}
\ce{H2C = CH - CH - CH2 - CH2 - CH3}\\
|\phantom{...............}\\
\ce{OH}\phantom{............}
\end{array}\]

एक शब्द/वाक्यांश उत्तर
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उत्तर

Hex-1-en-3-ol

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Alcohols, Phenols and Ethers - Intext Questions [पृष्ठ १९८]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 7 Alcohols, Phenols and Ethers
Intext Questions | Q 7.3 (iv) | पृष्ठ १९८

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IUPAC name of the compound is:

\[\begin{array}{cc}
\ce{CH3-CH-OCH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]


Give IUPAC name of the compound given below.

\[\begin{array}{cc}
\phantom{}\ce{CH3 - CH - CH2 - CH2 - CH - CH3}\phantom{.}\\
\phantom{.........}|\phantom{...................}|\phantom{...........}\\
\phantom{..}\ce{Cl}\phantom{.................}\ce{OH}\phantom{..}
\end{array}\]


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(i) \[\ce{CrO3}\] in anhydrous medium.

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Explain why p-nitrophenol is more acidic than phenol.


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  Column I Column II
(i) (a) Hydroquinone
(ii) (b) Phenetole
(iii) (c) Catechol
(iv) (d) o-Cresol
(v) (e) guinone
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    (g) Anisole

Assertion: p-nitrophenol is more acidic than phenol.

Reason: Nitro group helps in the stabilisation of the phenoxide ion by dispersal of negative charge due to resonance.


Write the IUPAC name of the following compound.


Write IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


Write structural formulae for:

p-Nitrophenol


Write IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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