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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Write IUPAC name of the following compound: CH3 OH

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प्रश्न

Write IUPAC name of the following compound:

एक शब्द/वाक्यांश उत्तर
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उत्तर

4-Methylphenol

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पाठ 7: Alcohols, Phenols and Ethers - Exercises [पृष्ठ २२२]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
पाठ 7 Alcohols, Phenols and Ethers
Exercises | Q 7.1 (vi) | पृष्ठ २२२

संबंधित प्रश्‍न

Name the following compound according to the IUPAC system.

\[\begin{array}{cc}
\ce{CH3 - C = C - CH2OH}\\
|\phantom{......}|\phantom{.....}\\
\ce{CH3}\phantom{.}\ce{Br}\phantom{....}\\
\end{array}\]


Give the IUPAC name of the following ether:

O2N – C6H4 – OCH3(p)


Ethylidene dichloride when boiled with aqueous solution of NaOH yields _______.

(A) formaldehyde

(B) acetaldehyde

(C) acetone

(D) ethyl methyl ketone


Write IUPAC name of the following compound (CH3)2 N − CH2CH3


Write IUPAC name of the following


Write IUPAC name of the following

\[\begin{array}{cc}\ce{CH3-CH-CH-CH2-OH}\\|\phantom{.....}|\phantom{.......}\\\ce{OH}\phantom{..}\ce{CH3}\phantom{.....}\end{array}\]


Write IUPAC names of the following


In a carbinol system of nomenclature tert.butyl alcohol is named as _______________


Give IUPAC names of the following compound:

\[\begin{array}{cc}
\phantom{..}\ce{H}\phantom{...}\ce{CH3}\phantom{.}\ce{H}\phantom{..}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{}\\
\ce{H - C - C - C - H}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{}\\
\phantom{.}\ce{H}\phantom{...}\ce{OH}\phantom{.}\ce{H}\phantom{.}\\
\end{array}\]


3-methylphenol is called ____________.


HBr reacts fastest with ____________.


n-Propyl alcohol and isopropyl alcohol can be chemically distinguished by which reagent?


When ethyl alcohol reacts with acetic acid, the products formed are:


\[\ce{HC ≡ CH ->[HgSO4][H2SO4] ->[CH3MgBr][H2O] ->[PBr3]}\]


Explain why p-nitrophenol is more acidic than phenol.


Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid.

Reason: Lewis acid polarises the bromine molecule.


Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.

Reason: Bromine polarises in carbon disulphide.


Draw structure of the following compound.

2. 5-Diethylphenol


Write IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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