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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Write structure of the compound whose IUPAC names is 3-Chloromethylpentan-1-ol - Chemistry

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प्रश्न

Write structures of the compounds whose IUPAC names are as follows:

3-Chloromethylpentan-1-ol.

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उत्तर

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संबंधित प्रश्‍न

Name the following compound according to IUPAC system.


Write IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3\phantom{.}}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


Write IUPAC name of the following compound:

\[\begin{array}{cc}
\ce{HO - CH2 - CH - CH2 - OH}\\
|\phantom{..}\\
\ce{OH}
\end{array}\]


What is the action of hot HI on it?


3-Methylbutane-2-ol on heating with HI gives ______


How is phenol converted into the following?

Benzene


How is phenol converted into the following?

picric acid


Write the IUPAC name of the following :


How do you convert the Ethanal to Propanone


Isopropyl alcohol on oxidation forms:


Give IUPAC names of the following compound:

\[\begin{array}{cc}
\phantom{..}\ce{H}\phantom{...}\ce{CH3}\phantom{.}\ce{H}\phantom{..}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{}\\
\ce{H - C - C - C - H}\\
\phantom{}|\phantom{....}|\phantom{....}|\phantom{}\\
\phantom{.}\ce{H}\phantom{...}\ce{OH}\phantom{.}\ce{H}\phantom{.}\\
\end{array}\]


C6H5OCH2CH3 is called:


Cresol has ____________.


n-Propyl alcohol and isopropyl alcohol can be chemically distinguished by which reagent?


\[\ce{Phenol ->[Zn, dust] 'X' ->[CH3Cl][Anhy. AlCl3] 'Y' ->[Alkaline][KMnO4] 'Z'}\]

The product ‘Z’ is:


IUPAC name of m-cresol is ______.


What happens when benzene diazonium chloride is heated with water?


Assertion: Addition reaction of water to but-1-ene in acidic medium yields butan-1-ol.

Reason: Addition of water in acidic medium proceeds through the formation of primary carbocation.


Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.

Reason: Bromine polarises in carbon disulphide.


Write IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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