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प्रश्न
Write the IUPAC name of the following compound:
C6H5 – O – C7H15(n−)
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उत्तर
1-Phenoxyheptane
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संबंधित प्रश्न
Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - O - CH2 - CH - CH3}\\
\phantom{................}|\\
\phantom{....................}\ce{CH3}
\end{array}\]
Write the IUPAC name of the following compound:
C6H5 – O – C2H5
Give the IUPAC name of the following ether:
Ethylidene dichloride when boiled with aqueous solution of NaOH yields _______.
(A) formaldehyde
(B) acetaldehyde
(C) acetone
(D) ethyl methyl ketone
How is phenol converted into the following?
benzoquinone
Write the structures of the products when Butan-2-ol reacts with SOCl2
In the dehydration of alcohols to alkenes by heating with concentrated sulphuric acid, the initiation step is:
(1) formation of carbonation
(2) formation of an ester
(3) protonation of the alcohol molecule
(4) elimination of water
Write structural formulae for Cyclohex-2-en-1-ol.
Write IUPAC name of the following
Write IUPAC names of the following
Glycerol is ____________.
3-methylphenol is called ____________.
Which of the following compounds is oxidised to prepare methyl ethyl ketone?
IUPAC name of the compound is:
\[\begin{array}{cc}
\ce{CH3-CH-OCH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
Assertion: Addition reaction of water to but-1-ene in acidic medium yields butan-1-ol.
Reason: Addition of water in acidic medium proceeds through the formation of primary carbocation.
Assertion: Phenols give o- and p-nitrophenol on nitration with conc. \[\ce{HNO3}\] and \[\ce{H2SO4}\] mixture.
Reason: –OH group in phenol is o–, p– directing.
Explain why Lewis acid is not required in bromination of phenol?
How can phenol be converted to aspirin?
Write a chemical reaction for the following conversion:
Acetic acid into ethyl alcohol.
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
