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प्रश्न
Write the structures of the products when Butan-2-ol reacts with SOCl2
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उत्तर
When butan-2-ol reacts with SOCl2, then 2-chlorobutane formed as a product.

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संबंधित प्रश्न
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\[\begin{array}{cc}
\phantom{..................}\ce{CH2OH}\\
\phantom{.........}|\\
\ce{CH3 - CH2 - CH - CH - CH - CH3}\\
\phantom{.........}|\phantom{...................}|\\
\phantom{.............}\ce{CH2Cl}\phantom{..........}\ce{CH3}\phantom{}
\end{array}\]
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\ce{CH3 - CH - OCH3}\\
\phantom{}|\phantom{....}\\
\phantom{}\ce{CH3}\phantom{..}
\end{array}\] is ______.
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\[\begin{array}{cc}
\phantom{}\ce{CH3 - CH - CH2 - CH2 - CH - CH3}\phantom{.}\\
\phantom{.........}|\phantom{...................}|\phantom{...........}\\
\phantom{..}\ce{Cl}\phantom{.................}\ce{OH}\phantom{..}
\end{array}\]
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\[\begin{array}{cc}
\phantom{}\ce{CH3 - CH2 - C = C - OH}\\
\phantom{........}|\phantom{....}|\phantom{}\\
\phantom{..............}\ce{CH3 CH2OH}
\end{array}\]
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\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
