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प्रश्न
Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.
Reason: Bromine polarises in carbon disulphide.
पर्याय
Assertion and reason both are correct and reason is correct explanation of assertion.
Assertion and reason both are wrong statements.
Assertion is correct statement but reason is wrong statement.
Assertion is wrong statement but reason is correct statement.
Both assertion and reason are correct statements but reason is not correct explanation of assertion.
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उत्तर
Assertion and reason both are wrong statements.
Explanation:
Phenol forms 2, 4, 6-tribromophenol on treatment with bromine in water. In phenols, the polarization of bromine takes place even in the absence of Lewis acid.
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संबंधित प्रश्न
Name the following compound according to the IUPAC system.
\[\begin{array}{cc}
\phantom{.....................................}\ce{CH2OH}\\
\phantom{............................}|\\
\ce{CH3 - CH - CH2 - CH - CH - CH3}\\
|\phantom{....................}|\phantom{............}\\
\ce{CH3}\phantom{..............}\ce{OH}\phantom{.........}\\
\end{array}\]
Name the following compound according to the IUPAC system.
\[\begin{array}{cc}
\ce{CH3 - C = C - CH2OH}\\
|\phantom{......}|\phantom{.....}\\
\ce{CH3}\phantom{.}\ce{Br}\phantom{....}\\
\end{array}\]
Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\phantom{........................}\ce{CH3}\\
\phantom{....................}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{.........}|\phantom{.........}|\\
\phantom{...}\ce{CH3}\phantom{....}\ce{OH}\phantom{....}\ce{CH3}\\
\end{array}\]
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\[\begin{array}{cc}
\ce{CH3CH-CH2Br ->[CH3O^-][CH3OH] is}\\
|\phantom{................}\\
\ce{CH3}\phantom{.............}
\end{array}\]
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| Column I | Column II | |
| (i) | ![]() |
(a) Hydroquinone |
| (ii) | ![]() |
(b) Phenetole |
| (iii) | ![]() |
(c) Catechol |
| (iv) | ![]() |
(d) o-Cresol |
| (v) | ![]() |
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| (vi) | ![]() |
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\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]






