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Write structural formula for pentane-1,4-diol.

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प्रश्न

Write structural formula for pentane-1,4-diol.

रासायनिक समीकरणे/रचना
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उत्तर

\[\begin{array}{cc}
\ce{H3C - HC - H2C - H2C - CH2 - OH}\\
|\phantom{......................}\\
\ce{\underset{Pentane-1,4-diol}{OH}\phantom{....................}}\\
\end{array}\]

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पाठ 11: Alcohols, Phenols and Ethers - Exercises [पृष्ठ २५३]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
पाठ 11 Alcohols, Phenols and Ethers
Exercises | Q 5.4 | पृष्ठ २५३

व्हिडिओ ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्‍न

Name the following compound according to the IUPAC system.

\[\begin{array}{cc}
\phantom{.....................................}\ce{CH2OH}\\
\phantom{............................}|\\
\ce{CH3 - CH - CH2 - CH - CH - CH3}\\
|\phantom{....................}|\phantom{............}\\
\ce{CH3}\phantom{..............}\ce{OH}\phantom{.........}\\
\end{array}\]


Write the IUPAC name of the following compound:

\[\begin{array}{cc}
\ce{CH3 - CH - CH - CH3}\\
|\phantom{.........}|\phantom{...}\\
\ce{OH}\phantom{....}\ce{OH}\\
\end{array}\]


Give the IUPAC name of the following ether:

\[\begin{array}{cc}
\ce{C2H5OCH2 - CH - CH3}\\
\phantom{.........}|\\
\phantom{.............}\ce{CH3}
\end{array}\]


Give the IUPAC name of the following ether:

O2N – C6H4 – OCH3(p)


Give the IUPAC name of the following ether:

CH3CH2CH2OCH3


Natalite is a mixture of

(a) diethyl ether and methanol

(b) diethyl ether and ethanol

(c) dimethyl ether and methanol

(d) dimethyl ether and ethanol


How is phenol converted into the following?

Benzene


Write IUPAC name of the following compound (CH3)2 N − CH2CH3


Write the IUPAC name of the following :


Write structural formulae for 1-Ethylcyclohexanol.


Write structural formulae for Cyclohex-2-en-1-ol.


Write IUPAC names of the following


Cresol has ____________.


The IUPAC name of the ether CH2 = CH–CH2OCH3 is:


The product of acid catalysed hydration of 2-phenylpropene is:


The correct acidic strength order of the following is:


     (I)


    (II)


     (III)


Give IUPAC name of the compound given below.

\[\begin{array}{cc}
\phantom{}\ce{CH3 - CH - CH2 - CH2 - CH - CH3}\phantom{.}\\
\phantom{.........}|\phantom{...................}|\phantom{...........}\\
\phantom{..}\ce{Cl}\phantom{.................}\ce{OH}\phantom{..}
\end{array}\]


Write the IUPAC name of the compound given below.

\[\begin{array}{cc}
\phantom{}\ce{CH3 - CH2 - C = C - OH}\\
\phantom{........}|\phantom{....}|\phantom{}\\
\phantom{..............}\ce{CH3 CH2OH}
\end{array}\]


Explain why p-nitrophenol is more acidic than phenol.


Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.

  Column I   Column II
(i) CH3—O—CH3 (a)
(ii) \[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
\backslash\phantom{.............}\\
\ce{CH-O-CH3}\\
/\phantom{..............}\\
\ce{CH3}\phantom{..................}
\end{array}\]
(b) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{CH3-C-I + CH3OH}\\
|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]
(iii) \[\begin{array}{cc}
\ce{CH3}\phantom{.}\\
|\phantom{....}\\
\ce{H3C-C-O-CH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
(c)
(iv) (d) CH3—OH + CH3—I
    (e) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-OH + CH3I}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (f) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-I + CH3OH}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (g) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{CH3-C-OH + CH3I}\\
|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]

Assertion: p-nitrophenol is more acidic than phenol.

Reason: Nitro group helps in the stabilisation of the phenoxide ion by dispersal of negative charge due to resonance.


Assertion: Phenol forms 2, 4, 6 – tribromophenol on treatment with \[\ce{Br2}\] in carbon disulphide at 273 K.

Reason: Bromine polarises in carbon disulphide.


How are the following conversions carried out?

Methyl magnesium bromide→2-Methylpropan-2-ol.


Draw structure of the following compound.

2-Methoxypropane


Draw structure of the following compound.

Prop-2-en-1-ol


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