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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Write structural formula for pentane-1,4-diol.

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प्रश्न

Write structural formula for pentane-1,4-diol.

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उत्तर

\[\begin{array}{cc}
\ce{H3C - HC - H2C - H2C - CH2 - OH}\\
|\phantom{......................}\\
\ce{\underset{Pentane-1,4-diol}{OH}\phantom{....................}}\\
\end{array}\]

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पाठ 11: Alcohols, Phenols and Ethers - Exercises [पृष्ठ २५३]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
पाठ 11 Alcohols, Phenols and Ethers
Exercises | Q 5.4 | पृष्ठ २५३

व्हिडिओ ट्यूटोरियलVIEW ALL [3]

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\[\begin{array}{cc}
\ce{H3C - CH - CH2 - CH - CH - CH2 - CH3}\\
|\phantom{....................}|\phantom{.........}|\phantom{.............}\\
\ce{OH}\phantom{................}\ce{OH}\phantom{...}\ce{C{_2}H5}\phantom{.........}\\
\end{array}\]


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\[\begin{array}{cc}
\ce{CH3 - CH - CH - CH3}\\
|\phantom{.........}|\phantom{...}\\
\ce{OH}\phantom{....}\ce{OH}\\
\end{array}\]


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\[\begin{array}{cc}
\ce{CH3CH-CH2Br ->[CH3O^-][CH3OH] is}\\
|\phantom{................}\\
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\end{array}\]


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\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C  -CH3}\\
\phantom{.}|\phantom{......}|\phantom{......}|\\
\phantom{....}\ce{CH3\phantom{...}\ce{OH}\phantom{...}\ce{CH3}}\
\end{array}\]


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