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प्रश्न
Write structural formulae for 1-Ethylcyclohexanol.
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उत्तर
1-Ethylcyclohexanol
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संबंधित प्रश्न
Name the following compound according to the IUPAC system.
\[\begin{array}{cc}
\ce{H2C = CH - CH - CH2 - CH2 - CH3}\\
|\phantom{...............}\\
\ce{OH}\phantom{............}
\end{array}\]
Write the IUPAC name of the following compound:
Write IUPAC name of the following compound:
Write the IUPAC name of the following compound:
Write the IUPAC name of the following compound:
C6H5 – O – C2H5
Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{CH3 - CH2 - O - CH - CH2 - CH3}\\
\phantom{....}|\\
\phantom{........}\ce{CH3}
\end{array}\]
Give the IUPAC name of the following ether:
\[\begin{array}{cc}
\ce{C2H5OCH2 - CH - CH3}\\
\phantom{.........}|\\
\phantom{.............}\ce{CH3}
\end{array}\]
Give the IUPAC name of the following ether:
CH3OCH2CH2Cl
Give the IUPAC name of the following ether:
O2N – C6H4 – OCH3(p)
Give the IUPAC name of the following ether:
3-Methylbutane-2-ol on heating with HI gives ______
Write the IUPAC name of the following :
In the dehydration of alcohols to alkenes by heating with concentrated sulphuric acid, the initiation step is:
(1) formation of carbonation
(2) formation of an ester
(3) protonation of the alcohol molecule
(4) elimination of water
What.will be the product fonned when chlorobenzene is heated with sodium metal in the presence of dry ether?
Write structural formula for pentane-1,4-diol.
C6H5OCH2CH3 is called:
3-methylphenol is called ____________.
Butane-2-ol is ____________.
The IUPAC name of the ether CH2 = CH–CH2OCH3 is:
The product of acid catalysed hydration of 2-phenylpropene is:
\[\ce{Phenol ->[Zn, dust] 'X' ->[CH3Cl][Anhy. AlCl3] 'Y' ->[Alkaline][KMnO4] 'Z'}\]
The product ‘Z’ is:
IUPAC name of the compound \[\begin{array}{cc}
\ce{CH3 - CH - OCH3}\\
\phantom{}|\phantom{....}\\
\phantom{}\ce{CH3}\phantom{..}
\end{array}\] is ______.
Explain why p-nitrophenol is more acidic than phenol.
Assertion: Phenols give o- and p-nitrophenol on nitration with conc. \[\ce{HNO3}\] and \[\ce{H2SO4}\] mixture.
Reason: –OH group in phenol is o–, p– directing.
Give the structures of Thiosulphuric acid and Peroxy monosulphuric acid.
