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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid. Reason: Lewis acid polarises the bromine molecule.

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प्रश्न

Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid.

Reason: Lewis acid polarises the bromine molecule.

पर्याय

  • Assertion and reason both are correct and reason is correct explanation of assertion.

  • Assertion and reason both are wrong statements.

  • Assertion is correct statement but reason is wrong statement.

  • Assertion is wrong statement but reason is correct statement.

  • Both assertion and reason are correct statements but reason is not correct explanation of assertion.

MCQ
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उत्तर

Assertion is wrong statement but reason is correct statement.

Explanation:

Bromination of phenol cannot be carried out in presence of Lewis acid.

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पाठ 11: Alcohols, Phenols and Ethers - Multiple Choice Questions (Type - I) [पृष्ठ १६४]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
पाठ 11 Alcohols, Phenols and Ethers
Multiple Choice Questions (Type - I) | Q 66 | पृष्ठ १६४

संबंधित प्रश्‍न

What is metamerism? 


Write the IUPAC name of the following compound:

\[\begin{array}{cc}
\ce{CH3 - CH - CH - CH3}\\
|\phantom{.........}|\phantom{...}\\
\ce{OH}\phantom{....}\ce{OH}\\
\end{array}\]


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Write IUPAC name of the following compound:

\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


Write the IUPAC name.

\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C  -CH3}\\
\phantom{.}|\phantom{......}|\phantom{......}|\\
\phantom{....}\ce{CH3\phantom{...}\ce{OH}\phantom{...}\ce{CH3}}\
\end{array}\]


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\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{..}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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