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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid. Reason: Lewis acid polarises the bromine molecule.

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प्रश्न

Assertion: Like bromination of benzene, bromination of phenol is also carried out in the presence of Lewis acid.

Reason: Lewis acid polarises the bromine molecule.

विकल्प

  • Assertion and reason both are correct and reason is correct explanation of assertion.

  • Assertion and reason both are wrong statements.

  • Assertion is correct statement but reason is wrong statement.

  • Assertion is wrong statement but reason is correct statement.

  • Both assertion and reason are correct statements but reason is not correct explanation of assertion.

MCQ
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उत्तर

Assertion is wrong statement but reason is correct statement.

Explanation:

Bromination of phenol cannot be carried out in presence of Lewis acid.

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अध्याय 11: Alcohols, Phenols and Ethers - Multiple Choice Questions (Type - I) [पृष्ठ १६४]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 11 Alcohols, Phenols and Ethers
Multiple Choice Questions (Type - I) | Q 66 | पृष्ठ १६४

संबंधित प्रश्न

Name the following compound according to the IUPAC system.


  1. Draw the structures of all isomeric alcohols of molecular formula C5H12O and give their IUPAC names.
  2. Classify the isomers of alcohols in the above question as primary, secondary and tertiary alcohols.

Give the IUPAC name of the following ether:

CH3CH2CH2OCH3


Give the IUPAC name of the following ether:


Give reasons Fluoride ion has higher hydration enthalpy than chloride ion.


Write structural formula for pentane-1,4-diol.


Write IUPAC name of the following


HBr reacts fastest with ____________.


\[\ce{HC ≡ CH ->[HgSO4][H2SO4] ->[CH3MgBr][H2O] ->[PBr3]}\]


Which of the following gives a positive iodoform test?


\[\ce{Phenol ->[Zn, dust] 'X' ->[CH3Cl][Anhy. AlCl3] 'Y' ->[Alkaline][KMnO4] 'Z'}\]

The product ‘Z’ is:


Among the following sets of reactants which one produces anisole?


The correct acidic strength order of the following is:


     (I)


    (II)


     (III)


Give IUPAC name of the compound given below.

\[\begin{array}{cc}
\phantom{}\ce{CH3 - CH - CH2 - CH2 - CH - CH3}\phantom{.}\\
\phantom{.........}|\phantom{...................}|\phantom{...........}\\
\phantom{..}\ce{Cl}\phantom{.................}\ce{OH}\phantom{..}
\end{array}\]


Explain why p-nitrophenol is more acidic than phenol.


Match the starting materials given in Column I with the products formed by these (Column II) in the reaction with HI.

  Column I   Column II
(i) CH3—O—CH3 (a)
(ii) \[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
\backslash\phantom{.............}\\
\ce{CH-O-CH3}\\
/\phantom{..............}\\
\ce{CH3}\phantom{..................}
\end{array}\]
(b) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{CH3-C-I + CH3OH}\\
|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]
(iii) \[\begin{array}{cc}
\ce{CH3}\phantom{.}\\
|\phantom{....}\\
\ce{H3C-C-O-CH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
(c)
(iv) (d) CH3—OH + CH3—I
    (e) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-OH + CH3I}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (f) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-I + CH3OH}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (g) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{CH3-C-OH + CH3I}\\
|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]

Draw structure of the following compound.

2. 5-Diethylphenol


Draw structure of the following compound.

2-Methoxypropane


Write the IUPAC name.

\[\begin{array}{cc}
\phantom{................}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C  -CH3}\\
\phantom{.}|\phantom{......}|\phantom{......}|\\
\phantom{....}\ce{CH3\phantom{...}\ce{OH}\phantom{...}\ce{CH3}}\
\end{array}\]


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