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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Explain why p-nitrophenol is more acidic than phenol.

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प्रश्न

Explain why p-nitrophenol is more acidic than phenol.

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उत्तर

The electron-withdrawing group (−NO2), withdraws electrons and disperses the negative charge. Therefore, the −NO2 group stabilizes the phenoxide ion. Hence p-nitrophenol is more acidic than phenol.

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अध्याय 11: Alcohols, Phenols and Ethers - Multiple Choice Questions (Type - I) [पृष्ठ १६०]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 11 Alcohols, Phenols and Ethers
Multiple Choice Questions (Type - I) | Q 53 | पृष्ठ १६०

संबंधित प्रश्न

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\[\begin{array}{cc}
\ce{H2C = CH - CH - CH2 - CH2 - CH3}\\
|\phantom{...............}\\
\ce{OH}\phantom{............}
\end{array}\]


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\[\begin{array}{cc}
\ce{H3C - CH - CH2 - CH - CH - CH2 - CH3}\\
|\phantom{....................}|\phantom{.........}|\phantom{.............}\\
\ce{OH}\phantom{................}\ce{OH}\phantom{...}\ce{C{_2}H5}\phantom{.........}\\
\end{array}\]


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(ii) \[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
\backslash\phantom{.............}\\
\ce{CH-O-CH3}\\
/\phantom{..............}\\
\ce{CH3}\phantom{..................}
\end{array}\]
(b) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{CH3-C-I + CH3OH}\\
|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]
(iii) \[\begin{array}{cc}
\ce{CH3}\phantom{.}\\
|\phantom{....}\\
\ce{H3C-C-O-CH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
(c)
(iv) (d) CH3—OH + CH3—I
    (e) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-OH + CH3I}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (f) \[\begin{array}{cc}
\ce{CH3}\phantom{.....................}\\
\backslash\phantom{.................}\\
\ce{CH-I + CH3OH}\\
/\phantom{.................}\\
\ce{CH3}\phantom{.....................}
\end{array}\]
    (g) \[\begin{array}{cc}
\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
\ce{CH3-C-OH + CH3I}\\
|\phantom{.......}\\
\ce{CH3}\phantom{....}
\end{array}\]

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\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]


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\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{.............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3\phantom{...}OH\phantom{...}CH3}\\
\end{array}\] 


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