Advertisements
Advertisements
Question
Explain why p-nitrophenol is more acidic than phenol.
Advertisements
Solution
The electron-withdrawing group (−NO2), withdraws electrons and disperses the negative charge. Therefore, the −NO2 group stabilizes the phenoxide ion. Hence p-nitrophenol is more acidic than phenol.
APPEARS IN
RELATED QUESTIONS
Write the IUPAC name of the following compound:
\[\begin{array}{cc}
\ce{HO - CH2 - CH - CH2 - OH}\\
|\phantom{...}\\
\ce{OH}\phantom{.}\\
\end{array}\]
- Draw the structures of all isomeric alcohols of molecular formula C5H12O and give their IUPAC names.
- Classify the isomers of alcohols in the above question as primary, secondary and tertiary alcohols.
What is the action of hot HI on it?
3-Methylbutane-2-ol on heating with HI gives ______
Write the structures of the products when Butan-2-ol reacts with CrO3
What.will be the product fonned when chlorobenzene is heated with sodium metal in the presence of dry ether?
Write structural formula for Methyl vinyl ether.
Write structural formulae for 1-Ethylcyclohexanol.
Write IUPAC names of the following
The compound HOCH2 – CH2OH is __________.
HBr reacts fastest with ____________.
n-Propyl alcohol and isopropyl alcohol can be chemically distinguished by which reagent?
IUPAC name of the compound is:
\[\begin{array}{cc}
\ce{CH3-CH-OCH3}\\
|\phantom{....}\\
\ce{CH3}\phantom{..}
\end{array}\]
Which of the following reagents can be used to oxidise primary alcohols to aldehydes?
(i) \[\ce{CrO3}\] in anhydrous medium.
(ii) \[\ce{KMnO4}\] in acidic medium.
(iii) Pyridinium chlorochromate.
(iv) Heat in the presence of Cu at 573 K.
What happens when benzene diazonium chloride is heated with water?
Write complete reaction for the bromination of phenol in aqueous and non-aqueous medium.
How can phenol be converted to aspirin?
Convert the following:
Ethyl alcohol into ethyl acetate.
Write IUPAC name of the following compound:
\[\begin{array}{cc}
\phantom{...............}\ce{CH3}\\
\phantom{............}|\\
\ce{CH3 - CH - CH - C - CH3}\\
|\phantom{......}|\phantom{......}|\\
\phantom{...}\ce{CH3}\phantom{...}\ce{OH}\phantom{...}\ce{CH3}
\end{array}\]
